A) Urea
B) Benzamide
C) Acetamide
D) Thiourea
Correct Answer: A
Solution :
Equivalent of \[N{{H}_{3}}\] evolved \[=\frac{100\times 0.1\times 2}{1000}-\frac{20\times 0.5}{1000}\] \[=\frac{1}{100}\] percent of nitrogen in the unknown organic compound \[=\frac{1}{100}\times \frac{14}{0.3}\times 100=46.6\]% percent of nitrogen in urea \[{{(N{{H}_{2}})}_{2}}CO\] \[=\frac{14\times 2}{60}\times 100=46.6\]% \[\therefore \] The compound must be urea.You need to login to perform this action.
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