A) 750 J
B) 650 J
C) 350 J
D) 250 J
Correct Answer: A
Solution :
m = Z i t Þ \[i=\frac{m}{Zt}=\frac{0.99}{0.00033\times 1200}=2.5A\] Hence heat generated in the coil is \[H={{i}^{2}}Rt={{(2.5)}^{2}}\times 0.1\times 1200\]= 750 JYou need to login to perform this action.
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