| Metal X is found in earth's crust. This metal forms a reddish brown substance when exposed to moist air. When a blue colored solution Y is stored in a container made of X, the solution turns green and a reddish brown metal Z gets deposited on the container. |
| X, Y and Z are respectively |
A) \[Cu,CuS{{O}_{4}},Fe\]
B) \[Zn,ZnS{{O}_{4}},Fe\]
C) \[Fe,CuS{{O}_{4}},Cu\]
D) \[Cu,FeS{{O}_{4}},Fe\]
Correct Answer: C
Solution :
Metal X is Fe which is found in earth's crust. \[\underset{(X)}{\mathop{\underset{Iron}{\mathop{2Fe}}\,}}\,+\underset{Moist\,air}{\mathop{\frac{3}{2}{{O}_{2}}+x{{H}_{2}}O}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} (Rust) \\ (Reddish\,brown) \end{smallmatrix}}{\mathop{F{{e}_{2}}{{O}_{3}}.x{{H}_{2}}O}}\,\] \[\underset{\begin{smallmatrix} (Iron) \\ \,\,\,\,(X) \end{smallmatrix}}{\mathop{F{{e}_{(s)}}}}\,+\underset{\begin{smallmatrix} Copper\,sulphat \\ (blue\,coloured \\ solution)\,(Y) \end{smallmatrix}}{\mathop{CuS{{O}_{4}}_{(aq)}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} Iron\,sulphate \\ (green\,coloured \\ solution \end{smallmatrix}}{\mathop{FeS{{O}_{4(aq)}}}}\,+\underset{\begin{smallmatrix} Copper \\ (reddish \\ brown)\,(Z) \end{smallmatrix}}{\mathop{C{{u}_{(s)}}}}\,\]
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