A) X and Y were lead nitrate and potassium iodide solutions. The yellow precipitate Z was lead iodide.
B) X and Y were potassium chloride solution and water. The yellow precipitate Z was of chloride ion.
C) X and Y were sodium hydroxide solution and hydrochloric acid and the yellow precipitate Z was sodium chloride.
D) X and Y were potassium hydroxide solution and nitric acid and the yellow precipitate Z was potassium nitrate.
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} Lead\,nitrate \\ (Colourless\,solution) \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,(X) \end{smallmatrix}}{\mathop{Pb{{(N{{O}_{3}})}_{2(aq)}}}}\,+\underset{\begin{align} & Potassium \\ & iodide \\ & (Colourless\,solution) \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(Y) \\ \end{align}}{\mathop{2K{{I}_{(aq)}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} Lead\,iodide \\ (Yellow\,ppt.) \\ \,\,\,\,\,\,\,\,\,(Z) \end{smallmatrix}}{\mathop{Pb{{I}_{2(s)}}}}\,+\underset{\begin{smallmatrix} Potassium \\ nitrate \end{smallmatrix}}{\mathop{2KN{{O}_{3(aq)}}}}\,\] This is a double displacement or precipitation reaction.
You need to login to perform this action.
You will be redirected in
3 sec
