A) (32, 48)
B) (48, 32)
C) (- 32, 48)
D) (48, -32)
Correct Answer: A
Solution :
Let pole be\[({{x}_{1}},\ {{y}_{1}})\]. Then the equation of the polar is, \[x{{x}_{1}}+y{{y}_{1}}={{a}^{2}}\] \[\therefore \ x{{x}_{1}}+y{{y}_{1}}=64\] ?. (i) Since (i) and line \[2x+3y=4\] represent the same straight line. \[\Rightarrow \frac{{{x}_{1}}}{2}=\frac{{{y}_{1}}}{3}=\frac{-64}{-4}\Rightarrow {{x}_{1}}=32,\ {{y}_{1}}=48\] Trick: Pole\[\left( \frac{-l{{a}^{2}}}{n},\ \frac{-m{{a}^{2}}}{n} \right)\Rightarrow (32,\ 48)\].You need to login to perform this action.
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