A) 4
B) -4
C) 16
D) -16
Correct Answer: C
Solution :
The common chord of given circles is \[2x-6y-4-a=0\] .....(i) Since, x2 + y2 = 4 bisects the circumference of the circle x2 + y2 ? 2x + 6y + a = 0, therefore, (i) passes through the centre of second circle i.e., (1, ? 3). \ 2 + 18 ? 4 ?a = 0 Þ a = 16.You need to login to perform this action.
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