A) \[{{x}^{2}}+{{y}^{2}}-2ay=0\]
B) \[{{x}^{2}}+{{y}^{2}}+ay=0\]
C) \[{{x}^{2}}+{{y}^{2}}+ax=0\]
D) \[{{x}^{2}}+{{y}^{2}}-ax=0\]
Correct Answer: D
Solution :
Let chord AB is \[y=mx\] .....(i) Equation of CM, \[x+my=\lambda \] It is passing through (a, 0) \[\therefore \] \[x+my=a\] .....(ii) From (i) and (ii), \[x+y.\,\frac{y}{x}=a\]Þ \[{{x}^{2}}+{{y}^{2}}=ax\] \[\Rightarrow \]\[{{x}^{2}}+{{y}^{2}}-ax=0\] is the locus of the centre of the circle.You need to login to perform this action.
You will be redirected in
3 sec