question_answer

The radius of the circle, having centre at (2,1) whose one of the chord is a diameter of the circle \[{{x}^{2}}+{{y}^{2}}-2x-6y+6=0\] is  [IIT Screening 2004]

A)            1    

B)            2

C)            3    

D)            \[\sqrt{3}\]

Correct Answer: C

Solution :

            The centre of the given circle is (1, 3) and radius is 2. So, AB is a diameter of the given circle has its mid point as (1, 3). The radius of the required circle is 3.