A) \[x{{y}_{1}}+y{{x}_{1}}={{a}^{2}}\]
B) \[{{x}_{1}}+{{y}_{1}}=a\]
C) \[x{{x}_{1}}+y{{y}_{1}}=x_{1}^{2}+y_{1}^{2}\]
D) \[x{{x}_{1}}+y{{y}_{1}}={{a}^{2}}\]
Correct Answer: C
Solution :
\[T={{S}_{1}}\] is the equation of desired chord, hence \[x{{x}_{1}}+y{{y}_{1}}-{{a}^{2}}=x_{1}^{2}+y_{1}^{2}-{{a}^{2}}\Rightarrow x{{x}_{1}}+y{{y}_{1}}=x_{1}^{2}+y_{1}^{2}\].
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