A) \[x-y=0\]
B) \[x+y=0\]
C) \[x+y={{a}^{2}}+{{b}^{2}}\]
D) \[x-y={{a}^{2}}-{{b}^{2}}\]
Correct Answer: A
Solution :
We know that the equation of common chord is \[{{S}_{1}}-{{S}_{2}}=0\], where \[{{S}_{1}}\] and \[{{S}_{2}}\] are the equations of given circles, therefore \[{{(x-a)}^{2}}+{{(y-b)}^{2}}+{{c}^{2}}-{{(x-b)}^{2}}-{{(y-a)}^{2}}-{{c}^{2}}=0\] \[\Rightarrow 2bx-2ax+2ay-2by=0\] \[\Rightarrow 2(b-a)x-2(b-a)y=0\Rightarrow x-y=0\].You need to login to perform this action.
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