A) \[{{x}^{2}}+{{y}^{2}}+x+3y=0\]
B) \[{{x}^{2}}+{{y}^{2}}-x+3y=0\]
C) \[{{x}^{2}}+{{y}^{2}}+x-3y=0\]
D) \[{{x}^{2}}+{{y}^{2}}-x-3y=0\]
Correct Answer: D
Solution :
Let the midpoint of chord be (h, k), then its equation is \[T={{S}_{1}}\] i.e., \[{{(p-x)}^{2}}=4qy\] \[={{h}^{2}}+{{k}^{2}}-2h-6k-10\] Since it passes through the origin, therefore \[{{h}^{2}}+{{k}^{2}}-h-3k=0\] or locus is \[{{x}^{2}}+{{y}^{2}}-x-3y=0\].You need to login to perform this action.
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