A) 4
B) 2
C) 5
D) None of these
Correct Answer: D
Solution :
Here radius of circle is \[AC=\sqrt{{{\left( \frac{1}{2} \right)}^{2}}+{{\left( \frac{1}{2} \right)}^{2}}+1}=\sqrt{\frac{3}{2}}\] and \[CB=\sqrt{{{\left( \frac{3}{2} \right)}^{2}}+{{\left( \frac{1}{2} \right)}^{2}}}=\sqrt{\frac{10}{4}}=\sqrt{\frac{5}{2}}\] Now \[A{{B}^{2}}=A{{C}^{2}}-B{{C}^{2}}=\frac{3}{2}-\frac{5}{2}=-1\] \[\Rightarrow \]There is no possible value for AB. Aliter : Since the point (1, 1) lies outside the circle, therefore no such chord exist.You need to login to perform this action.
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