A) \[{{x}^{2}}+{{y}^{2}}-2x-2y=0\]
B) \[{{x}^{2}}+{{y}^{2}}=4\]
C) \[{{x}^{2}}+{{y}^{2}}=2\]
D) \[{{(x-1)}^{2}}+{{(y-2)}^{2}}=5\]
Correct Answer: C
Solution :
Let the mid-point of chord is (h,k). Also radius of circle is 2. Therefore \[\frac{OC}{OB}=\cos {{45}^{o}}\Rightarrow \frac{\sqrt{{{h}^{2}}+{{k}^{2}}}}{2}=\frac{1}{\sqrt{2}}\Rightarrow {{h}^{2}}+{{k}^{2}}=2\] Hence locus is\[{{x}^{2}}+{{y}^{2}}=2\].You need to login to perform this action.
You will be redirected in
3 sec