A) \[4\,cm\]
B) \[4\sqrt{2}\,cm\]
C) \[4\sqrt{3}\]
D) None of these
Correct Answer: B
Solution :
[b] \[\Delta BOD\]is a right angled triangle as. \[\angle BOD=90{}^\circ \] So, \[DO=BO=4\] and \[B{{D}^{2}}=D{{O}^{2}}+B{{O}^{2}}\] \[BD=\sqrt{{{4}^{2}}+{{4}^{2}}}=4\sqrt{2}\,cm\] |
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