A) \[{{44}^{{}^\circ }}\]
B) \[{{46}^{{}^\circ }}\]
C) \[{{66}^{{}^\circ }}\]
D) \[{{78.5}^{{}^\circ }}\]
Correct Answer: C
Solution :
(c): Single, angle subtentd on the circumference is half of the angle subtend on center. \[\therefore \]\[\angle ACB=\frac{1}{2}\angle AOB\] \[=\frac{1}{2}\times {{48}^{{}^\circ }}={{24}^{{}^\circ }}\] In \[\Delta MCB,\] \[\angle C+\angle B+\angle M={{180}^{{}^\circ }}\] \[\Rightarrow \]\[{{24}^{{}^\circ }}+\angle B+{{90}^{{}^\circ }}={{180}^{{}^\circ }}\] \[\therefore \]\[\angle B={{66}^{{}^\circ }}\]You need to login to perform this action.
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