A) \[{{53}^{{}^\circ }}\]
B) \[{{43}^{{}^\circ }}\]
C) \[{{40}^{{}^\circ }}\]
D) \[{{36}^{{}^\circ }}\]
Correct Answer: D
Solution :
(d): \[\angle BOD={{180}^{{}^\circ }}-{{108}^{{}^\circ }}={{72}^{{}^\circ }}\] Since, \[\angle BOD\]is an angle made by arc BD on centre. Here, \[\angle BCD\] is an angle made by arc BC on circumference. \[\therefore \] \[\angle BCD=\frac{1}{2}\times \angle BOD\] \[=\frac{1}{2}\times {{72}^{{}^\circ }}={{36}^{{}^\circ }}\]
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