A) 17 cm
B) 8 cm
C) 4 cm
D) 15 cm
Correct Answer: B
Solution :
Given, AD = 34 cm, AB = 30 cm \[\therefore \]\[AO=\frac{1}{2}AD=\frac{1}{2}(34)=17\,cm\] Draw \[OP\bot AB.\] Since, perpendicular drawn center to the chord bisects the chord. \[\therefore \] \[AP=\frac{1}{2}AB=15\,cm\] Now, in right angled \[\Delta APO\] \[{{(OP)}^{2}}={{(17)}^{2}}-{{(15)}^{2}}\] \[=289-225=64\] \[\Rightarrow \]\[OP=8\,cm\] \[\therefore \]Distance of AB from the center of the circle is 8 cm.You need to login to perform this action.
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