A) \[90{}^\circ \]
B) \[42{}^\circ \]
C) \[48{}^\circ \]
D) \[38{}^\circ \]
Correct Answer: C
Solution :
PQRS is a cyclic quadrilateral. \[\Rightarrow \]\[\angle P+\angle R={{180}^{o}}\] \[\Rightarrow \]\[\angle P={{180}^{o}}-{{135}^{o}}={{42}^{o}}\] In \[\Delta PQS,\angle P+\angle Q+\angle S={{180}^{o}}\] \[\therefore \]\[\angle PQS={{48}^{o}}\]
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