A) \[{{210}^{o}}\]
B) \[{{150}^{o}}\]
C) \[{{160}^{o}}\]
D) \[{{120}^{o}}\]
Correct Answer: B
Solution :
In quadrilateral YBQX \[\angle YXQ=\frac{1}{2}\]reflex \[\angle QBY=\frac{1}{2}\times {{210}^{o}}={{105}^{o}}\] PQ is a straight line \[\Rightarrow \] \[\angle PXY+\angle YXQ={{180}^{o}}\] (linear pair) \[\Rightarrow \] \[\angle PXY={{180}^{o}}-{{105}^{o}}={{75}^{o}}\] Now, in quadrilateral PAYX \[\angle PXY=\frac{1}{2}\angle PAY\] \[\therefore \] \[\angle PAY=2\angle PXY={{150}^{o}}\]You need to login to perform this action.
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