9th Class Mathematics Circles Question Bank Circles

  • question_answer
    O is the centre of the circle as shown in the figure.\[\angle QRP={{35}^{o}}\]and the distance between P and Q through 'O' is 4 cm. What is the measure of\[\angle ROQ?\]

    A) \[55{}^\circ \]                       

    B) \[35{}^\circ \]

    C) \[105{}^\circ \]              

    D) \[70{}^\circ \]

    Correct Answer: A

    Solution :

    Since \[PQ=4cm=2\times OQ\] \[=2\times radius,\]PQ is the diameter of circle, Join \[RQ.\,\,\angle PRQ={{90}^{o}}.\](Angle in a semicircle.) \[\therefore \]\[\angle ORQ={{90}^{o}}-{{35}^{o}}={{55}^{o}}\] But \[OR=OQ.\] \[\therefore \]\[\angle ORQ=\angle OQR={{55}^{o}}\]


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