A) \[55{}^\circ \]
B) \[35{}^\circ \]
C) \[105{}^\circ \]
D) \[70{}^\circ \]
Correct Answer: A
Solution :
Since \[PQ=4cm=2\times OQ\] \[=2\times radius,\]PQ is the diameter of circle, Join \[RQ.\,\,\angle PRQ={{90}^{o}}.\](Angle in a semicircle.) \[\therefore \]\[\angle ORQ={{90}^{o}}-{{35}^{o}}={{55}^{o}}\] But \[OR=OQ.\] \[\therefore \]\[\angle ORQ=\angle OQR={{55}^{o}}\]You need to login to perform this action.
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