A) \[s-b\]
B) \[2s+h\]
C) \[b+s\]
D) \[3b-s\]
Correct Answer: A
Solution :
According to question, \[s=\frac{a+b+c}{2}\,\,\Rightarrow \,\,2s=a+b+c\] B is external point and BD and BF are tangents and from an external point the tangents drawn to a circle are equal in length. \[\therefore \] \[BD=BF;~\] \[AF=AE;\] \[CD=CE\] s = Semi perimeter \[=\frac{AB+AC+BC}{2}\] \[2s=AB+AC+BC\] \[2s=AF+FB+AE+EC+BD+DC\] \[\Rightarrow \] \[2s=2AE+2CE+2BD\] \[\Rightarrow \] \[s=AE+CE+BD\] \[\Rightarrow \] \[s=AC+BD\Rightarrow s-b=BD\].You need to login to perform this action.
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