(p) Join AB. |
(q)\[\angle ABC={{90}^{o}}\]and\[\angle ABC={{90}^{o}}\](Angle in semicircle) |
(r)\[\angle ABD+\angle ABC={{360}^{o}}\] |
(s) DBC is a straight line segment. Hence B lies on the line segment DC. |
A) p
B) q
C) r
D) s
Correct Answer: C
Solution :
(r) is incorrect. The correct step should be \[\angle ABD+\angle ABC={{180}^{o}},\]for DBC to be a straight line segmentYou need to login to perform this action.
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