A) 5 cm
B) 8 cm
C) 10 cm
D) 6 cm
Correct Answer: B
Solution :
\[OM\bot PQ\] \[\Rightarrow \]M is the mid-point of PQ Join OQ. Now, in rt. \[\Delta {\mathrm O}\Mu Q,\]we have \[M{{Q}^{2}}=O{{Q}^{2}}-O{{M}^{2}}\] \[\Rightarrow \]\[MQ=\sqrt{16}=4\,cm\] \[\therefore \]\[PQ=2\times MQ=2\times 4=8\,cm\]
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