A) 30 cm
B) 24 cm
C) 16 cm
D) 18 cm
Correct Answer: C
Solution :
Given \[AB=12\,cm\Rightarrow AM=MB=6\,cm\] In \[\Delta OMA,O{{A}^{2}}=O{{M}^{2}}+A{{M}^{2}}\] \[\Rightarrow \]\[OA=\sqrt{100}=10\,cm\] \[\therefore \]Radius \[=OA=OC=10\,cm\] In \[\Delta ONC,O{{C}^{2}}=O{{N}^{2}}+N{{C}^{2}}\] \[\Rightarrow \]\[NC=\sqrt{64}=8\,cm\] \[\therefore \]Length of the chord \[=2\times NC=16\,cm\]You need to login to perform this action.
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