A) Greater than \[90{}^\circ \]
B) Less than \[90{}^\circ \]
C) Equal to \[180{}^\circ \]
D) Equal to \[90{}^\circ \]
Correct Answer: D
Solution :
\[\angle POQ=2\angle R\Rightarrow \angle POQ=2l\] In \[\Delta PQO,OP=OQ=r\] \[\Rightarrow \]\[\angle OQP=\angle OPQ=m\] Also, \[\angle OPQ+\angle OQP+\angle POQ={{180}^{o}}\] \[\Rightarrow \]\[m+m+2l={{180}^{o}}\] \[\Rightarrow \]\[m+l={{90}^{o}}\]You need to login to perform this action.
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