10th Class Mathematics Circles Question Bank Circles

  • question_answer
    In the given figure, 0 is the centre of in circle inscribed in\[\Delta \text{ABC}\]. Find \[\angle \text{BOC}\]if\[\angle \text{BAC}=\text{4}0{}^\circ \].

    A)  \[~\text{1}00{}^\circ \]    

    B)                         \[\text{12}0{}^\circ \]

    C)  \[~\text{9}0{}^\circ \]                  

    D)        \[~\text{11}0{}^\circ \]

    Correct Answer: D

    Solution :

     AO is joined. Since the circle is the in circle for\[\Rightarrow \], AO, BO and CO are the angle bisectors of \[{{6}^{x}}\] and \[\therefore \]respectively. \[{{6}^{x}}\] \[{{x}^{3}}\] In \['x'\] From the figure, \[\text{(25}\times \text{7)cm}\] \[~(\text{2}\times \text{52}\times \text{73) cm}\]

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