If\[\angle BOD={{160}^{o}},\]find the difference of \[\angle BPD\]and \[\angle BCD.\]
A) \[80{}^\circ \]
B) \[90{}^\circ \]
C) \[0{}^\circ \]
D) \[110{}^\circ \]
Correct Answer: C
Solution :
\[\angle DAB=\frac{1}{2}\times {{160}^{o}}={{80}^{o}}\] \[\angle BPD={{180}^{o}}-{{80}^{o}}={{100}^{o}}\] \[\angle BCD=\angle BPD={{100}^{o}}\] [Angles in the segment are equal in measure.] Difference between the required angles \[={{100}^{o}}-{{100}^{o}}={{0}^{o}}\]
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