A) \[{{41}^{o}}\]
B) \[{{23}^{o}}\]
C) \[{{67}^{o}}\]
D) \[{{18}^{o}}\]
Correct Answer: A
Solution :
\[\angle QPS=\angle QPR+\angle SPR\] \[={{67}^{o}}+{{72}^{o}}={{139}^{o}}\] PQRS is a cyclic quadrilateral. \[\therefore \]\[\angle QRS+\angle QPS={{180}^{o}}\] \[\Rightarrow \]\[\angle QRS={{180}^{o}}-{{139}^{o}}={{41}^{o}}\]You need to login to perform this action.
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