A) 1 : 3
B) 5 : 6
C) 2 : 3
D) None of these
Correct Answer: B
Solution :
Given, PQRS is a cyclic quadrilateral. \[\therefore \] \[\angle PSR+\angle PQR=\angle QPS+\angle QRS={{180}^{o}}\] \[\Rightarrow \]\[2y+3y=2x+4x\] \[\Rightarrow \]\[5y=6x\Rightarrow \frac{x}{y}=\frac{5}{6}\]i.e., 5 : 6You need to login to perform this action.
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