A) C - 1
B) C - 2
C) C - 3
D) C - 5
Correct Answer: B
Solution :
\[^{1}C{{H}_{3}}-{{\,}^{2}}\underset{\begin{smallmatrix} | \\ \underset{6}{\mathop{C}}\,{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\, \end{smallmatrix}}{\overset{\begin{smallmatrix} \overset{5}{\mathop{C}}\,{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\, \\ | \end{smallmatrix}}{\mathop{C-{{\,}^{3}}C{{H}_{2}}\,}}}\,-\,{}^{4}C{{H}_{3}}\] \[C-2\] is quaternary carbon because it is attached to 4 other carbon atoms.You need to login to perform this action.
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