A) \[{{(C{{H}_{3}})}_{2}}CH-C{{H}_{2}}CH=C{{H}_{2}}\]
B) \[{{(C{{H}_{3}})}_{2}}CH-CH=CH-C{{H}_{3}}\]
C) \[{{(C{{H}_{3}})}_{2}}CH-C{{H}_{2}}CH=CH-C{{H}_{3}}\]
D) \[{{(C{{H}_{3}})}_{2}}C=CHC{{H}_{2}}C{{H}_{3}}\]
Correct Answer: B
Solution :
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