A) Ethyl formic acid
B) Ethyl carboxylic acid
C) Ethane methanoic acid
D) Propanoic acid
Correct Answer: D
Solution :
\[\underset{\text{Propanoic acid}}{\mathop{\underset{3}{\mathop{C{{H}_{3}}}}\,\underset{2}{\mathop{C{{H}_{2}}}}\,\underset{1}{\mathop{COOH}}\,}}\,\]You need to login to perform this action.
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