A) (0, 0), (- 2, - 3)
B) (0, 0), (- 4, 0)
C) (0, 0), (2, 3)
D) None of these
Correct Answer: B
Solution :
(b): \[{{(x+2)}^{2}}+{{(0-3)}^{2}}={{\left( \sqrt{13} \right)}^{2}}\] \[\Rightarrow \] \[{{(x+2)}^{2}}+9=13\] \[\Rightarrow \] \[{{(x+2)}^{2}}=4\] \[\Rightarrow \] \[(x+2)=\pm \,2\] \[\Rightarrow \] \[x=2-2\] or, \[x=-2-2\] \[\Rightarrow \] \[x=0\] or, \[x=-4\]You need to login to perform this action.
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