A) \[a+b+c\]
B) abc
C) \[{{\left( a+b+c \right)}^{2}}\]
D) 0
Correct Answer: D
Solution :
(d): Area of triangle \[=\frac{1}{2}\left[ a\left( c+a-a-b \right)+b\left( a+b-b-c \right)+c\left( b+c-c-a \right) \right]\] \[=\frac{1}{2}\left[ ac-ab+ba-be+cb-ca \right]=0.\]You need to login to perform this action.
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