A) 12 sq. units
B) 8 sq. units
C) 6 sq. units
D) 4 sq. units
Correct Answer: D
Solution :
(d): Let the given vertices be A (3, 4) and C (5, 6). Length of \[AC=\sqrt{{{(3-5)}^{2}}+{{(4-6)}^{2}}}=\sqrt{8}\]units Area of the square = \[\frac{A{{C}^{2}}}{2}=\frac{{{\left( \sqrt{8} \right)}^{2}}}{2}~\]= 4sq.unitsYou need to login to perform this action.
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