• question_answer The extremities of the diagonal of a parallelogram are the points (3, -4) and (-6, 5).Third vertex is the point (-2, 1). Find its fourth vertex. A)  (1, 1)                     B)         (1, 0) C)  (0, 1)                     D)         (-1, 0)

In parallelogram ABCD, opposite sides are equal. $\frac{bc}{\sqrt{{{b}^{2}}+{{c}^{2}}}}$$\therefore$ $=\sqrt{64+36}=10\,cm$$\frac{PB}{PC}=\frac{AP}{DP}$ $\frac{PB}{PC}=\frac{AP}{DP}$$\Rightarrow$                         ....(1) Similarly, $x=\frac{1740}{29}=60$ $\Rightarrow$$140\times 605=11\times L.C.M.$                   .....(2) Now solve by substituting the points in the options. D (-1, 0) satisfies eqs. (1) and (2).