A) 3
B) 5
C) 2
D) 6
Correct Answer: B
Solution :
Let A(0,0), B(a,5)and C(-5,5) be the vertices of the triangle. Therefore, \[\Delta \text{APB }\tilde{\ }\text{ }\Delta \text{DPC}\] \[\Rightarrow \] \[\frac{AP}{DP}=\frac{PB}{PC}=\frac{AB}{DC}\] \[\Rightarrow \] \[AP\times PC=PB\times DP\] \[\frac{1}{2}\sqrt{{{b}^{2}}+{{c}^{2}}}\times AD=\frac{1}{2}bc\] \[\Rightarrow \]\[AD=\frac{bc}{\sqrt{{{b}^{2}}+{{c}^{2}}}}\]You need to login to perform this action.
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