10th Class
Mathematics
Coordinate Geometry
Question Bank
Co-ordinate Geometry
question_answer
The area of a triangle whose vertices are (-4, 0), (2, 4) and (4, 0) is
A) 8
B) 12
C) 16
D) 32
Correct Answer:
C
Solution :
Draw a triangle with given vertices. As we know that area of the triangle is given by \[A=\frac{1}{2}\] (Base) (Height) So, we have to find the base and height of a triangle. Base, \[b=4-(-4)=8\] For finding height, drop a perpendicular from \[(2,4)\] on to the base of a triangle as shown below Height, \[h=\sqrt{{{(2-2)}^{2}}+{{(4-0)}^{2}}}\] \[=\sqrt{16}=4\] \[\therefore \] Area of given triangle \[=\frac{1}{2}\times b\times h\] \[=\frac{1}{2}\times 8\times 4=16\]