A) k = - 4 and p = 0
B) k = 0 and p = - 4
C) k = -2 and p = 0
D) k = 0 and p = -2
Correct Answer: B
Solution :
Here, we are given that co-ordinates of vertice R is \[(4,0)\] and O is origin. So its co- :' u Snates are \[(0,0)\]. By distance rule, \[OR=\sqrt{{{(0-0)}^{2}}+{{(4-0)}^{2}}}=4.\] So, one side of square OPQR is \[OR=4\] \[\therefore \] \[OP=4\] Now, P is on y - axis and below x - axis, So, its x-co-ordinate is 0 and its y-co-ordinate is negative. Co-ordinate of P are \[(k,p)=(0,-4)\] i.e. \[k=0\]and \[p=-4\]You need to login to perform this action.
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