A) \[10\,\pi \]
B) \[13\,\pi \]
C) \[24\,\pi \]
D) \[26\,\pi \]
Correct Answer: B
Solution :
Here, the points \[A\,(2,0)\] and \[B\,(8,-4)\] are the end points of diameter AB. So, by distance formula Diameter, \[AB=\sqrt{{{(-4-0)}^{2}}+{{(8-2)}^{2}}}\] \[=\sqrt{16+36}=\sqrt{52}\] \[=\sqrt{4\times 13}=2\sqrt{13}\] \[\therefore \] Radius \[=\frac{2\sqrt{13}}{2}=\sqrt{13}\] Now, area of the circle \[=\pi \] (radius)2 \[=\pi (\sqrt{13})2=13\pi \]You need to login to perform this action.
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