A) - 1
B) 7
C) 6
D) 4
Correct Answer: A
Solution :
The given points \[(0,4),\,(4,0)\] and \[(5,p)\] are collinear, if \[\frac{1}{2}[{{x}_{1}}({{y}_{2}}-{{y}_{3}})+{{x}_{2}}({{y}_{3}}-{{y}_{1}})+{{x}_{3}}({{y}_{1}}-{{y}_{2}})]=0\] or \[\frac{1}{2}[0\,(0-p)+4(p-4)+5(4-0)]=0\] or \[4p-16+20=0\] \[\therefore \] \[p=-1\]You need to login to perform this action.
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