question_answer

A graph plotted between log K vs 1/T for calculating activation energy is shown by           [MP PET 2002]

A)                

B)                

C)                     

D)                

Correct Answer: B

Solution :

           A graph plotted between \[\log k\,\,\text{Vs}\,\frac{1}{T}\] for calculating activation energy is shown as                    from Arrhenius equation                    \[\log \,\,k=\log \,\,A-\frac{{{E}_{A}}}{2.303\,\,RT}\]