A) 34
B) 54
C) 100
D) 50
Correct Answer: B
Solution :
\[\log \frac{{{K}_{2}}}{{{K}_{1}}}=\frac{{{E}_{a}}}{2.303R}\left[ \frac{1}{{{T}_{1}}}-\frac{1}{{{T}_{2}}} \right]\] If \[\frac{{{K}_{2}}}{{{K}_{1}}}=2\] \[\log 2=\frac{{{E}_{a}}}{2.303\times 8.314}\left[ \frac{1}{300}-\frac{1}{310} \right]\] \[{{E}_{a}}=.3010\times 2.303\times 8.314\left( \frac{300\times 310}{10} \right)\] \[=53598.59\ Jmo{{l}^{-1}}\] \[=54\ kJ\].
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