A) \[\ln \,k=\ln A-{{e}^{{{E}_{a}}/RT}}\]
B) \[\ln k=\ln A+{{e}^{{{E}_{a}}/RT}}\]
C) \[\ln k=\ln A-{{e}^{RT/{{E}_{a}}}}\]
D) All of these
Correct Answer: A
Solution :
Arrhenius suggested an equation which describes rate constant (K) as a function of temperature. \[K=A{{e}^{-{{E}_{a}}/RT}}\] \[\ln K=\ln A-{{e}^{{{E}_{a}}/RT}}\]You need to login to perform this action.
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