JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Collision theory, Energy of activation and Arrhenius equation

  • question_answer
    Temperature dependent equation can be written as [Orrisa JEE 2005]

    A)                 \[\ln \,k=\ln A-{{e}^{{{E}_{a}}/RT}}\]      

    B)                 \[\ln k=\ln A+{{e}^{{{E}_{a}}/RT}}\]

    C)                 \[\ln k=\ln A-{{e}^{RT/{{E}_{a}}}}\]         

    D)                 All of these

    Correct Answer: A

    Solution :

               Arrhenius suggested an equation which describes rate constant (K) as a function of temperature.                    \[K=A{{e}^{-{{E}_{a}}/RT}}\]                                 \[\ln K=\ln A-{{e}^{{{E}_{a}}/RT}}\]


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