A) \[2.5\times {{10}^{-5}}\]
B) \[1.5\times {{10}^{-4}}\]
C) \[3.125\times {{10}^{-6}}\]
D) \[6.25\times {{10}^{-4}}\]
Correct Answer: C
Solution :
\[{{C}_{6}}{{H}_{5}}COON{{H}_{4}}\to {{C}_{6}}{{H}_{5}}CO{{O}^{-}}+NH_{4}^{+}\] \[0.5-\frac{.25}{100}\] \[\frac{.25}{100}\] \[\frac{.25}{100}\] According to Ostwald dilution law. \[K=\frac{{{\alpha }^{2}}C}{1-\alpha }\] \[\left( \therefore \ \ \alpha =\frac{.25}{100} \right)\] \[K={{\alpha }^{2}}C\] \[\left( \because \ \ 1-\alpha =\text{Very small} \right)\] \[K=\frac{.25}{100}\times \frac{.25}{100}\times .5\] ; \[K=3.125\times {{10}^{-6}}\]
You need to login to perform this action.
You will be redirected in
3 sec
