A) \[2\times {{10}^{-4}}\]moles per litre
B) \[6\times {{10}^{-6}}\]moles per litre
C) \[1.2\times {{10}^{-5}}\]moles per litre
D) \[8\times {{10}^{-4}}\]moles per litre
Correct Answer: A
Solution :
\[A{{g}_{2}}S\]⇌\[2A{{g}^{+}}+{{S}^{-\,\,-}}\] \[{{K}_{sp}}=4{{S}^{3}}\] \[S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}\]\[=\sqrt[3]{\frac{3.2\times {{10}^{-11}}}{4}}=2\times {{10}^{-6}}\]You need to login to perform this action.
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