A) More
B) Less
C) Equal
D) Zero
Correct Answer: B
Solution :
\[AgCl\to \underset{x}{\mathop{A{{g}^{=}}}}\,+\underset{x}{\mathop{C{{l}^{-}}}}\,\] After NaCl is added x \[x+1\times {{10}^{-4}}\] That is why \[A{{g}^{+}}\] will be less.You need to login to perform this action.
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