A) \[2\times {{10}^{-4}}\]
B) \[4\times {{10}^{-4}}\]
C) \[5.6\times {{10}^{-6}}\]
D) \[3.1\times {{10}^{-4}}\]
Correct Answer: A
Solution :
\[A{{X}_{2}}\to \underset{x}{\mathop{A}}\,\ \ +\ \ \underset{2x}{\mathop{2X}}\,\] \[{{K}_{sp}}=4{{x}^{3}}\] ; \[x=\sqrt[3]{\frac{3.2\times {{10}^{-11}}}{4}}\]; \[x=2\times {{10}^{-4}}\]mole/litre.You need to login to perform this action.
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