A) \[2.0\times {{10}^{-6}}M\]
B) \[1.0\times {{10}^{-4}}M\]
C) \[1.6\times {{10}^{-4}}M\]
D) \[4.0\times {{10}^{-10}}M\]
Correct Answer: B
Solution :
\[M{{X}_{2}}\] ⇌ \[\underset{S\,\,\,\,\,\,}{\mathop{{{M}^{2+}}}}\,+\underset{2S\,\,\,}{\mathop{2{{X}^{-}}}}\,\] \[{{K}_{sp}}={{(2S)}^{2}}(S)=4{{S}^{3}}\] Þ \[S=2\,\,\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{4\times {{10}^{-12}}}{4}}=1.0\times {{10}^{-4}}M\].You need to login to perform this action.
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